## How do you find the exact value of sin 105?

sin (105) = sin (15 + 90) = cos 15. Apply the trig identity: cos2x=2cos2x−1. sin(105)=cos(15)=√2+√32.

## How do you find the exact value of a trigonometric function CSC?

First find the angle coterminal to 17π6 that falls between 0 and 2π : 17π6−2π=5π6 . So we know that csc(17π6)=csc(5π6) . csc(x)=1sin(x) and we know that sin(5π6)=12 because it’s from the Unit Circle.

**What is the exact value of csc?**

You cannot get an exact value; Considering that csc(x)=1sin(x) and that sin(π)=0 you get: csc(π)=1sin(π)=10 which cannot be calculated.

**What is the csc of 60?**

Trigonometry Examples The exact value of csc(60) is 2√3 .

### What is the exact value of sin 60?

√3/2

From the above equations, we get sin 60 degrees exact value as √3/2.

### What is the exact value of sin 75 degrees?

Hence, the exact functional value of sin75 is 1+√32√2.

**What is the exact value of sin 15 degrees?**

Value of Sin 15 degree = (√3 – 1) / 2√2.

**How to find the exact value of sin ( 105 )?**

Split 105 105 into two angles where the values of the six trigonometric functions are known. Apply the sum of angles identity. The exact value of sin(45) sin ( 45) is √2 2 2 2.

#### How to find the exact value of CSC ( 60 )?

The exact value of csc(60) csc (60) is 2 √3 2 3. 2 √3 2 3 Multiply 2 √3 2 3 by √3 √3 3 3. 2 √3 ⋅ √3 √3 2 3 ⋅ 3 3

#### How to find sin 45, cos 45 and sin 60?

sin (105) = sin (15 + 90) = cos 15. First find (cos 15). Call cos 15 = cos x Apply the trig identity: cos2x = 2cos2x − 1. sin(105) = cos(15) = √2 + √3 2. Check by calculator. √2 +√3 2 = 1.93 2 = 0.97. OK = ( √3 2)( 1 √2) + (1 2)( 1 √2) = √2 4 ((√3 +1) = 0.9656 nearly. sin 45, cos 45 and sin 60 are irrational. So, the answer is a surd.

**How to find the exact value of SEC?**

Combine and simplify the denominator. Tap for more steps… Multiply 2 √ 3 2 3 and √ 3 √ 3 3 3. Raise √ 3 3 to the power of 1 1. Raise √ 3 3 to the power of 1 1. Use the power rule a m a n = a m + n a m a n = a m + n to combine exponents. Add 1 1 and 1 1.