## How do you solve a distributed load problem?

To use a distributed load in an equilibrium problem, you must know the equivalent magnitude to sum the forces, and also know the position or line of action to sum the moments. The line of action of the equivalent force acts through the centroid of area under the load intensity curve.

## Is weight a distributed load?

In many situations a surface area of a body is subjected to a distributed load. Such forces are caused by winds, fluids, or the weight of items on the body’s surface. This is a uniform load along one axis of a flat rectangular body.

**What is the unit of uniformly distributed load?**

The load may be represented as rate per lineal metre (kN/m) for beams, or as a rate per square metre (kN/m2) for slabs. A diagram shows a beam with the load distributed all along its length. The load is labelled UDL with units shown as kN/m or kN/m2.

**What is the difference between point load and distributed load?**

Point load (P) is a force applied at a single infinitismal point at a set distance from the ends of the beam. Uniform distributed load (q) is a force applied over an area, denoted by q which is force per unit length. End slope (θ) is the angle that the beam makes at the end after it is deflected by the load.

### What is the second equation in distributed loads?

If the forces are further restricted so that they all lie in the x-y plane, then z’ = 0 and only the second equation applies. If instead of a system of point loads, consider a continuous distributed force f (x) that acts in the x-y plane and is parallel to the y axis, then through calculus the second equation (x’) above becomes

### How are distributed loads used in statics problems?

In many static problems, applied loads are given as distributed force loads. This is similar to stacking sand bags on a beam so that the load is distributed across the beam instead of at one location (point load). To help make the problem easier to solve, it is convenient to convert the distributed load into equivalent point loads.

**How to reduce the distribution of a load?**

REDUCTION OF A SIMPLE DISTRIBUTED LOADING REDUCTION OF A SIMPLE DISTRIBUTED LOADING Today’s Objectives: Students will be able to determine an equivalent force for a distributed load. APPLICATIONS A distributed load on the beam exists due to the weight of the lumber.

**How are distributed loads calculated for a triangle?**

Distributed Loads For a triangle, this would be ½ the base times the maximum intensity. 15 Distrubuted Loads Monday, November 5, 2012 Distributed Loads The location of the equivalent point load will be 2/3 of the distance from the smallest value in the loading diagram. 16 Distrubuted Loads Monday, November 5, 2012 9 Distributed Loads